How to include .txt on Qt

[mrjj]

@KzR69100

• So the QColor col is my returned color that is right ?
  Yes, the Color to look for.

• i don't understand the "CostInfo& ci"

It means a reference to a CostInfo.
We ask the map to return the CostInfo for the key and instead of
having it as a copy we actually point to the one in the list.
so if you do

ci.Cost = 100; you would update the one in the list.

if we did
CostInfo ci = Costs[col.rgb()];
It would make a copy and ci would be a copy and not point to one in the list.

So if it was integers and a normal list.
int a= List[1]; // copy
int &a = List[1]; // a points to the int in index [1]

• And do the size of the picture in the Qmap have to be resized?

The qmap only store the file names of the images
I assume you are adding the images to a QRes file
http://www.bogotobogo.com/Qt/Qt5_Resource_Files.php
So all images are build into the program
and then load them with ":/" syntax.
That would be easy and fast.
http://doc.qt.io/qt-5/resources.html

for(int x = topLeft.x(); x < maxX; ++x) {
		for(int y = topLeft.y(); y < maxY; ++y) {
			image.setPixelColor(x, y, colour);
                                              if (Costs.contains( colour.rgb() )) {          // it will be that ?  YES
                                                   CostInfo& ci = Costs[colour.rgb()];
                                                     int Cost = ci.Cost;
                                                      Pixmap pix( ci.ImageName ); 
		}  
	}
}

to have all RGB in my struct can i use a "for" (sorry to always say "can i use a for") but the problem is that i want all RGB value with my 15 - 20 pictures

Not sure what you are asking here :)
Are you asking how to use a FOR with the QMAP `?
u can do

QMapIterator<QRgb, CostInfo >i(Costs);
while (i.hasNext()) {
    i.next();
    cout << i.key() << ": " << i.value().Cost << endl;
}

Pleases read
http://doc.qt.io/qt-5/qmap.html

[KzR69100]

thanks,

i already read the doc for Qmap,

my question was the same as before (sorry) i asked that if i got a square who have a color like ( 255 , 2 , 2 - It's near red ) how can i display a red file because on my Qmap i have only

QColor(250,0,0).rgb(), { "C:\Users\David\Desktop\Red\strawberry", 10) (i will use :/ after created my QRes file)

the i.hasNext is the answer to my question right ? he will found a value next to his value ?

My other question was that i have to browse all my picture with a double for (because i got 50 square in my picture)

so i have to put the

if (Costs.contains( colour.rgb() )) {          
                                                  CostInfo& ci = Costs[colour.rgb()];
                                                    int Cost = ci.Cost;
                                                     Pixmap pix( ci.ImageName );

and then the while (i.hasNext()) ?

[mrjj]

@KzR69100

• my question was the same as before (sorry) i asked that if i got a square who have a color like ( 255 , 2 , 2 - It's near red )

For that you need to a function that can compare the RGB values.
And if Base Color and the color you come with ( from image) is
within some threshold you also accept it.
http://stackoverflow.com/questions/9018016/how-to-compare-two-colors
like
bool IsCloseColor( QColor c1, QColor c2 ) {
// this you must fill in . read link.
}
If you want a clever mathcing , this is also interresting
http://stackoverflow.com/questions/2103368/color-logic-algorithm

• the i.hasNext is the answer to my question right ? he will found a value next to his value ?
  Yes the code shown will go over map. Just like a "For"
  Something like:

  QMapIterator<QRgb, CostInfo >i(Costs);
  while (i.hasNext()) {
    i.next();
    QColor BaseColor( i.key() );
    if (Costs.contains( colour.rgb() ) || IsCloseColor(BaseColor, colour)   )  {
      CostInfo& ci = Costs[colour.rgb()];
      int Cost = ci.Cost;
      QPixmap pix( ci.ImageName );
    }
  }// while

[KzR69100]

i got :

bool IsCloseColor( QColor c1, QColor c2 ) {
	int diffRed   = Math.abs(c1.red() - c2.red());
	int diffGreen = Math.abs(c1.green() - c2.green());
	int diffBlue  = Math.abs(c1.blue()  - c2.blue());

	if (diffBlue+diffRed+diffGreen< z){	// i block for the z how can i say "the smallest" ?
		return c1;


	}
}

i got a lot of errors, i tried to google it but no answer :

like : request for meme "key in 'i'", which is of non-class type 'int'

template argument 2 is invalid (QMap<QRgb, CostInfo ">" Costs =)

scalar object 'Costs' requires one element in initializer

[mrjj]

@KzR69100

z you must decide for.
Best is to test with different colors and see how close its still ok.

With the exact code and the exact line it's impossible to say what error comes from.

You can try my test project. It compiles and you can test the color matching.
https://www.dropbox.com/s/6mc3e4qe375qzih/mylookup.zip?dl=0

[KzR69100]

My code is : (cpp)

#include "mainwindow.h"
#include "ui_mainwindow.h"
#include <QPixmap>
#include <QImage>
#include <QFileDialog>
#include <QColor>
#include <QPoint>
#include <QSize>
#include <iostream>
using namespace std;


QColor Couleurdominante(const QImage& image, const QPoint& topLeft, const QSize& rectSize);
void Remplissage(QImage& image, const QPoint& topLeft, const QSize& rectSize, const QColor& colour);


MainWindow::MainWindow(QWidget *parent) :
	QMainWindow(parent),
	ui(new Ui::MainWindow)
{
		ui->setupUi(this);

}


MainWindow::~MainWindow()
{
	delete ui;
}




void MainWindow::on_push_clicked()
{
	QString fileName = QFileDialog::getOpenFileName(this,
	tr("Open Image"), "/", tr("Image Files (*.png *.jpg *.bmp)"));
	QPixmap pix(fileName);
	ui->label->setPixmap(pix);
	const QSize s = pix.size();
	pixi = QImage(pix.toImage());

	ui->label_2->setText( "Size: " + QString::number(s.width()) +" "+ QString::number(s.height()) );

}

void MainWindow::on_push2_clicked()
{


	for (int i=0;i<pixi.width();i+=a){
						 for (int j=0;j<pixi.height();j+=b){
	Remplissage(pixi,QPoint(i,j),QSize(a,b),Couleurdominante(pixi,QPoint(i,j),QSize(a,b)));
	}}

	pixa=QPixmap::fromImage(pixi);
	ui->label_3->setPixmap(pixa);

}




void Remplissage(QImage& image, const QPoint& topLeft, const QSize& rectangle, const QColor& colour) {

	int maxX = topLeft.x() + rectangle.width();
	int maxY = topLeft.y() + rectangle.height();

	for(int x = topLeft.x(); x < maxX; ++x) {
		for(int y = topLeft.y(); y < maxY; ++y) {
			image.setPixelColor(x, y, colour);
			QMapIterator<QRgb, CostInfo >i;
			while (i.hasNext()) {
				i.next();
				QColor BaseColor( i.key() );
				if (Costs.contains( colour.rgb() ) || IsCloseColor(BaseColor, colour) )  {
					CostInfo& ci = Costs[colour.rgb()];
					int Cost = ci.Cost;
					QPixmap pix( ci.ImageName );
				}
			}
		}
	}
}


QColor Couleurdominante(const QImage & image,const QPoint & topLeft, const QSize & rectangle)
{
		int rouge = 0, vert = 0, bleue = 0;

		int  X = topLeft.x() + rectangle.width();
		int  Y = topLeft.y() + rectangle.height();

		for (int y = topLeft.y(); y < Y; y++)  {
				for (int x = topLeft.x(); x < X; x++)   {
						QRgb pixel = image.pixel(x, y);

						rouge += qRed(pixel);
						vert += qGreen(pixel);
						bleue += qBlue(pixel);
				}
		}

		int n = rectangle.width() * rectangle.height();

		Q_ASSERT(n);
		if (n <= 0)
				return Qt::black;

		return QColor(rouge / n, vert / n, bleue / n);
}



QMap<QRgb, CostInfo > Costs = {
	{ QColor(255 , 0 , 0 ).rgb(), { "://fraise.png", 10 }},
	{ QColor(0 , 255 , 0 ).rgb(), { "://balleverte.png", 20 }},
	{ QColor(0 , 0 , 255 ).rgb(), { "://ballebleue.png", 20 }},
	{ QColor(255 , 255 , 255 ).rgb(), { "://balleblanche.png", 20 }},
	{ QColor(255 , 128 , 0 ).rgb(), { "://ballepeche.png", 20 }},
	{ QColor(0 , 0 , 0 ).rgb(), { "://noir.png", 20 }},
	{ QColor(102 , 51 , 0 ).rgb(), { "://marron.png", 20 }},
	{ QColor(255 , 102 , 78 ).rgb(), { "://rose.png", 20 }},
	{ QColor(0 , 204 , 204 ).rgb(), { "://turquoise.png", 20 }},
	{ QColor(255 , 178 , 102 ).rgb(), { "://beige.png", 20 }},
	{ QColor(76 , 0 , 153 ).rgb(), { "://violet.png", 20 }},
	{ QColor(100 , 100 , 100 ).rgb(), { "://gris.png", 20 }},
};

bool IsCloseColor( QColor c1, QColor c2 ) {
	int diffRed   = Math.abs(c1.red() - c2.red());
	int diffGreen = Math.abs(c1.green() - c2.green());
	int diffBlue  = Math.abs(c1.blue()  - c2.blue());

	if (diffBlue+diffRed+diffGreen< 100){	/
		return c1;


	}
}

i took z = 100. For the moment

.h :

#ifndef MAINWINDOW_H
#define MAINWINDOW_H

#include <QMainWindow>
#include <QPixmap>
#include <QPoint>
#include <QSize>
#include <iostream>

namespace Ui {
	class MainWindow;
}

class MainWindow : public QMainWindow
{
	Q_OBJECT

public:
	explicit MainWindow(QWidget *parent = 0);


	~MainWindow();





private slots:
	void on_push_clicked();
	struct CostInfo {
		QString ImageName;
		int Cost;
	};

	void on_push2_clicked();

	void on_verticalSlider_sliderMoved(int position);

private:
	Ui::MainWindow *ui;
	QImage pixi;
	QPixmap pixa;
	int a;
	int b;
};

#endif // MAINWINDOW_H

[mrjj]

Hi
In your
bool IsCloseColor( QColor c1, QColor c2 ) {
int diffRed = Math.abs(c1.red() - c2.red());
int diffGreen = Math.abs(c1.green() - c2.green());
int diffBlue = Math.abs(c1.blue() - c2.blue());

if (diffBlue+diffRed+diffGreen< 100){	/
	return c1; <<<<<< you should return true
    else //////////////////you need this part also
       return false;  /////////

[KzR69100]

Thank you i corrected.

And for my other error ?

in : if (Costs.contains( colour.rgb() ) || IsCloseColor(BaseColor, colour) )

for the function IsCloseColor, its not better to return a color ? like QColor IsCloseColor();, i don't understand what we can do if we return "false" or "true"

[Payx]

i up ! need help ^^

[Payx]

for the function IsCloseColor, its not better to return a color ? like QColor IsCloseColor();, i don't understand what we can do if we return "false" or "true"

[mrjj]

@Payx

It just checks if the color is "close " to base color
No reason to return color ?
we say
if (Costs.contains( colour.rgb() ) || IsCloseColor(BaseColor, colour) )

So if we have direct match OR
the colour is close to BaseColor then we think its ok.

[Payx]

Okay thank you,

i have

diffBlue+diffRed+diffGreen< 100

but if many colors correspond ?
it can return many colors no ?

[mrjj]

@Payx
No it cant..
IsCloseColor tells if 2 colors are close. It return true/false.
it dont return any color. it tells you if they color u have "in the hand" matches the
base color given.
You already have the color (colour var) so no reason to return it.

[Payx]

So it cant be possible to have 2 colors who is <100 ?

[mrjj]

@Payx
ofc, just compare 2 times or more times. Once pr color.
IsCloseColor(BaseColor, col1)
IsCloseColor(BaseColor, col2)
IsCloseColor(BaseColor, col3)
....

[Payx]

So if i have like 27 colors, i have to do 27 function ?

[mrjj]

@Payx
No. use a list (of colors) and loop over it, checking each.

[Payx]

Okay, so it's useless to write :

bool IsCloseColor( QColor c1, QColor c2 ) {
	int diffRed   = Math.abs(c1.red() - c2.red());
	int diffGreen = Math.abs(c1.green() - c2.green());
	int diffBlue  = Math.abs(c1.blue()  - c2.blue());

	if (diffBlue+diffRed+diffGreen< 100){	/
		return true;.
		else
				return false;


	}
}

So if i understood well the "<100" is now useless. Can't we just return the color who have the minimum diffBlue+diffRed+diffGreen ?

[mrjj]

@Payx
The < 100 is the factor on How close the color was to the Base Color.
So i do not understand u think its useless.

How else would u compare them?

[Payx]

u said "do a list", instead of write ...<100, we can do a "for" and "return" the minimal "diffBlue+diffRed+diffGreen" or the all color no ?