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  4. How to pass multiple objects one after another in to loop..?

How to pass multiple objects one after another in to loop..?

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  • R Offline
    R Offline
    Rohith
    wrote on 5 Mar 2016, 10:15 last edited by Rohith 3 May 2016, 10:18
    #3

    Hi mrjj,

    Thanks for replying sorry for writing the question in such a enigmatic way.
    The thing i want to do is after creating multiple multiple qTableWidgetItems that can accept a selection in the form of checkboxes and when ever the user clicks on quit button all the checkboxes that are selected need to be unselected.

    a = new QTableWidgetItem("a");
    a->setCheckState(Qt::Unchecked);
    
    b = new QTableWidgetItem("b");
    b->setCheckState(Qt::Unchecked);
    
    .
    .
    .
    .
    
    z = new QTableWidgetItem("z");
    z->setCheckState(Qt::Unchecked);
    
    

    and i am unchecking them in the below way

    a->setCheckState(Qt::Unchecked);
    b->setCheckState(Qt::Unchecked);
    .
    .
    .
    z->setCheckState(Qt::Unchecked);
    
    

    To avoid huge no of lines i am trying to uncheck each item by passing the objects in to for loop as stated in above my post

    QStringList items;
    items<<"a"<<"b"<<....<<"z";
    
        for(int i=0; i<items.size(); i++)
        {
            QTableWidgetItem items.at(i) = new QTableWidgetItem;
        }
    
    

    Thanks in advance,
    Rohith.G

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    0
    • M Offline
      M Offline
      mrjj
      Lifetime Qt Champion
      wrote on 5 Mar 2016, 10:21 last edited by
      #4

      @mrjj said:
      Ok, but you have access to the items via the
      table->item(i, j);
      That is how you can get the items to uncheck them.
      What is wrong with that way?

      --
      this code makes no sense to me. Its not valid.
      Items is a stringlist so
      " QTableWidgetItem items.at(i)"
      makes no sense to me. you cannot write like that.
      Its a list of strings and have nothing to do with QTableWidgetItem.

        for(int i=0; i<items.size(); i++)
          {
              QTableWidgetItem items.at(i) = new QTableWidgetItem;
          }
      
      
      1 Reply Last reply
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      • R Offline
        R Offline
        Rohith
        wrote on 5 Mar 2016, 10:27 last edited by
        #5

        Hi mrjj,

        I have tried by following your method as below

        
            int iColumns = table->columnCount();
            int iRows = table->rowCount();
        
            for(int i = 0; i < iRows; ++i) {
              for(int j = 0; j < iColumns; ++j) {
                  qDebug("Inside the for loop");
                QTableWidgetItem* pWidget = table->item(i, j);
                pWidget->setCheckState(Qt::Unchecked);
        //        myList.append(pWigdet);
              }
            }
        

        But this is compiling fine and after running when ever the quit button is clicked
        It is entering into the slot but the gui was closing by apperance of below line
        "The program has unexpectedly finished."

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        • M Offline
          M Offline
          mrjj
          Lifetime Qt Champion
          wrote on 5 Mar 2016, 10:30 last edited by
          #6

          ok
          please insert check
          if (pWidget)
          pWidget->setCheckState(Qt::Unchecked);

          if it still crashes, then put break point on and see what line.

          Also, table is your table , correct ?
          You have new it and added the items to it?

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          • R Offline
            R Offline
            Rohith
            wrote on 5 Mar 2016, 10:39 last edited by
            #7

            Hi mrjj,

            Your Code was working and sorry to say this i have written the object name and display string name differently```

            //Previous Syntax
            z = new QTableWidgetItem("z");
            z->setCheckState(Qt::Unchecked);

            //New Syntax
            z = new QTableWidgetItem("X");
            z->setCheckState(Qt::Unchecked);

            
            Can you please help me to solve as per new requirement
            M 1 Reply Last reply 5 Mar 2016, 10:45
            0
            • R Rohith
              5 Mar 2016, 10:39

              Hi mrjj,

              Your Code was working and sorry to say this i have written the object name and display string name differently```

              //Previous Syntax
              z = new QTableWidgetItem("z");
              z->setCheckState(Qt::Unchecked);

              //New Syntax
              z = new QTableWidgetItem("X");
              z->setCheckState(Qt::Unchecked);

              
              Can you please help me to solve as per new requirement
              M Offline
              M Offline
              mrjj
              Lifetime Qt Champion
              wrote on 5 Mar 2016, 10:45 last edited by
              #8

              @Rohith
              Hi
              Good the other worked.

              Im not sure what you ask about ?
              you replace "z" with "X"

              So what do you need help with?

              R 1 Reply Last reply 5 Mar 2016, 10:56
              0
              • M mrjj
                5 Mar 2016, 10:45

                @Rohith
                Hi
                Good the other worked.

                Im not sure what you ask about ?
                you replace "z" with "X"

                So what do you need help with?

                R Offline
                R Offline
                Rohith
                wrote on 5 Mar 2016, 10:56 last edited by
                #9

                @mrjj

                The thing is that code that you have posted is working
                if the both the object name and displaying name are same then the the operation uncheck is working it means

                z = new QTableWidgetItem("z");
                z->setCheckState(Qt::Unchecked);

                in the above code z is the object name and the data present in double qoutes "z" is the data that display on GUI, your code was executing

                QTableWidgetItem* pWidget = table->item(i, j);
                table->item(i,j) is retreving the data that we are writing in the doublequotes which will display on GUI it was not retreving the object name of item that i have created using QTableWidgetItem *z(ObjectName) = new QTableWidgetItem("Z"(data displays on Gui));

                if(z(pWidget)
                z(pWidget)->setCheckState(Qt::Unchecked)

                but know i have changed my syntax to

                z = new QTableWidgetItem("X");
                z->setCheckState(Qt::Unchecked);

                Hope You understand now,
                Rohith.G

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                • M Offline
                  M Offline
                  mrjj
                  Lifetime Qt Champion
                  wrote on 5 Mar 2016, 11:01 last edited by
                  #10

                  sorry, im not sure i understand

                  z = new QTableWidgetItem("z");
                  z->setCheckState(Qt::Unchecked);

                  z is just a variable name of type QTableWidgetItem *
                  "z" is the Text for the QTableWidgetItem .

                  table->item(i, j); do not care how u inserted the items.
                  This would do the same

                  QTableWidgetItem *MyItem = new QTableWidgetItem("z");
                  MyItem->setCheckState(Qt::Unchecked);

                  and table->item(i, j) would still work.

                  R 1 Reply Last reply 5 Mar 2016, 11:08
                  1
                  • M mrjj
                    5 Mar 2016, 11:01

                    sorry, im not sure i understand

                    z = new QTableWidgetItem("z");
                    z->setCheckState(Qt::Unchecked);

                    z is just a variable name of type QTableWidgetItem *
                    "z" is the Text for the QTableWidgetItem .

                    table->item(i, j); do not care how u inserted the items.
                    This would do the same

                    QTableWidgetItem *MyItem = new QTableWidgetItem("z");
                    MyItem->setCheckState(Qt::Unchecked);

                    and table->item(i, j) would still work.

                    R Offline
                    R Offline
                    Rohith
                    wrote on 5 Mar 2016, 11:08 last edited by
                    #11

                    @mrjj

                    Sorry for my wrong assumption the Code working fine in any condition and thanks a lot for your help and answering my doubts patiently thankyou very much for you help

                    Rohith.G

                    M 1 Reply Last reply 5 Mar 2016, 11:34
                    1
                    • R Rohith
                      5 Mar 2016, 11:08

                      @mrjj

                      Sorry for my wrong assumption the Code working fine in any condition and thanks a lot for your help and answering my doubts patiently thankyou very much for you help

                      Rohith.G

                      M Offline
                      M Offline
                      mrjj
                      Lifetime Qt Champion
                      wrote on 5 Mar 2016, 11:34 last edited by
                      #12

                      @Rohith

                      np. sometimes its hard to understand the real issue
                      when seeing just part of code but
                      glad it worked :)

                      you are very welcome.

                      1 Reply Last reply
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                      5 Mar 2016, 11:34

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