[solved] How to properly delete a QLayoutItem from the layout
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Hi there!
I'm trying to delete a Widget out of a layout. The widget can be at an arbitrary (but existing) position and lower items have to move up to close the gap. layout_m is of type QLayout,. Here's my delete member function:
if(index >= layout_m->count() || index < 0) return;
QLayoutItem* toDelete = layout_m->takeAt(index);
if(toDelete != 0){
toDelete->widget()->setParent(NULL);
delete toDelete;
requestedCount_m--;
}
This code is inspired from the QLayout documentation's description how to properly delete all contents of a layout. However, as you see, I usetoDelete->widget()->setParent(NULL);to break ownership to the QLayoutItem. If I don't do that, the deleted item is still displayed in the parent widget, but not in the layout.
I conclude that my way to remove an item from a layout is unproper. How should I do that in a clean way?
Cheers,
Kalsan -
@kalsan As far as I know, QLayout::takeAt() doesn't remove the widget of the QLayoutItem from its parent widget.
So I think your code is ok. Anyway, take a look at QLayout::removeWidget. I don't know all your code, but maybe you should remove the widget from the layout using that method.
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I just call:
widgetToRemoveFromLayout.close(); delete widgetToRemoveFromLayout;everything else does the layout on its own.
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Yay, that's what I was looking for. Thanks!