Connect Signal with Argument via Lambda to Slot with Argument?

BDC_Patrick

Ok.. hi..

Following Situation:
I crated a QDialog with this Signals:

signals:
    void created(QString _path);
    void aborted();

Inside the Window, that calls this Dialog, i want to Connect a Slot:

private slots:
    void _onOpenproject(QString _path);

With the Dialogs Signal..

My current call and Connect is this:

void TGS_WindowProjectLibrary::_onNewProject() {
    TGS_Dialog_NewProject _newProj;
    connect(&_newProj,&TGS_Dialog_NewProject::created,this,[this]{ _onOpenproject();} );

    _newProj.exec();
}

Question now:
How to connect the SIGNALs QString with the SLOTs?

jsulm

@BDC_Patrick said in Connect Signal with Argument via Lambda to Slot with Argument?:

How to connect the SIGNALs QString with the SLOTs?

connect(&_newProj,&TGS_Dialog_NewProject::created,this,[this](QString str){ _onOpenproject(str);} );

But why don't you connect the signal directly to the slot?

J.Hilk

@BDC_Patrick
no need for a lambda here:

connect(&_newProj,&TGS_Dialog_NewProject::created,this, &TGS_WindowProjectLibrary::_onOpenproject);

if you insist on using a lambda;

connect(&_newProj,&TGS_Dialog_NewProject::created,this,[this](QString argument)->void{ _onOpenproject(argument);} );

BDC_Patrick

@jsulm & @J-Hilk

Thank you so much. You´re my Heroes :D

Everyday something new to learn :)