Is it possible to return an object of type QMap from a function call? It doesn't seem to like that I'm defining the function as a type QMap.

[QTNewbie2020]

Hi. I'm very, very, very new to Qt. I'm modifying a huge codeset (C++ in Linux OS) and am wondering if it is possible to return an object of type QMap from a function call? It doesn't seem to like that I'm defining the function as a type QMap.

Very simplified example:

QMap doSomeFunction(int)
{
QString someStringName;
QMap<QString, int> _someQMap;

someStringName = "abc";
someIntData = int + 1000;
_someQMap.insert(someStringName, someIntData);
return _someQMap;
}

void main
{
QMap <QString, int> _anotherQMap;

_anotherQMap = doSomeFunction(2);
return;
}

[David_001]

QMap<QString, int> doSomeFunction(int)
{
QString someStringName;
QMap<QString, int> _someQMap;

someStringName = "abc";
someIntData = int + 1000;
_someQMap.insert(someStringName, someIntData);
return _someQMap;
}

void main()
{
QMap <QString, int> _anotherQMap;

_anotherQMap = doSomeFunction(2);
return;
}

QMap<QString, int> doSomeFunction(int) /// <= do not forget to say which kind of qmap
{

}

[wrosecrans]

@QTNewbie2020 QMap isn't, by itself, a complete type. A function can't return a QMap in-general. QMap<QString, int> is what you declare inside the function, so you have to declare the function as return that specific type of QMap to have a complete type. A QMap<float, int> for example would be a completely different type as far a sthe compiler is concerned. They just look like similar names to a human.