Template: Force const parameter

kshegunov

I haven't tried it, but:

template<class T>
QList<const T *> libraryItems() const
{
    // ...
    QList<const T *> list;
    // ...
}

?

Joel Bodenmann

The problem with that is that then the user/caller of that method has to write code like this:

QList<const MyLibraryItem*> myLibraryItems = mimeData->libraryItems<MyLibraryItem*>();

In my opinion that is just a no-go. You'd expect the two template parameters to be the same in that assignment.

kshegunov

@Joel-Bodenmann
Actually:

QList<const MyLibraryItem *> myLibraryItems = mimeData->libraryItems<MyLibraryItem>();

But yes, they differ. Whether or not it's acceptable it's up to you, I know of no other way.

PS.
I think a fat notice in the docs should be just enough. This isn't c++11 so what's on the left can be different from what's on the right (i.e. there's no auto confusing code). It's still valid to write:

QWidget * button = new QToolButton();

Chris Kawa

Can I force the caller of that method to only use template types/parameters (the T thing) that are const pointers?

I'll just assume you really meant pointers to const, because const pointer would be LibraryItem* const, which is entirely different beast.

This is one of those cases where templates come really handy. Here's a stripped down implementation:

class LibraryMimeData
{
private:
    QList<const LibraryItem*> _libraryItems;

    // this general type will get rid of non-pointer and pointer to non-const types
    template<typename T, bool is_pointer_to_const> struct Foo {
        static inline QList<T> convert(const QList<const LibraryItem*>& items) = delete;
    };

    //the specialized type will only accept pointer to const types
    template<typename T> struct Foo<T, true> {
        static inline QList<T> convert(const QList<const LibraryItem*>& items)
        {
            return /* DO THE CONVERSION */;
        }
    };

public:
    //and here's a public interface
    template<typename T> QList<T> libraryItems() const {
        return Foo<T, std::is_pointer<T>::value && std::is_const<std::remove_pointer<T>::type>::value>::convert(_libraryItems);
    }
};

This way it will work for pointer to const types and will give a lovely error about using deleted function for all others.

kshegunov

Ahahah, I needed a couple of reads to get it. It's quite nifty, albeit pretty verbose.

Chris Kawa

@kshegunov Yeah, templates usually do that when it's not you who wrote them ;) I usually steer away from them if I can but when you need to deal with type system and avoid runtime overhead they are a very flexible tool.
The verbose part is an implementation detail. Commented well and renamed to something better than Foo can live happily in a codebase. The user facing function has a nice clean signature.

kshegunov

@Chris-Kawa said in Template: Force const parameter:

I usually steer away from them

Me too, which you can deduce from my simplistic answer :P
They're just marginally better than the preprocessor ... code writing code always perplexes me, I must admit ...

PS.
I must also give you credit for the partial specialization trick ... never would've come up with it myself.

Chris Kawa

They're just marginally better than the preprocessor

Awww, that's hurtful to the templates :) Preprocessor is just glorified find/replace machinery. Templates are a full blown, type safe, statically checked sub-language. Combined with constexpr they really have a Death-Star-like power (with similar caveats ;) )
I remember when I wrote template based compile time quick sort back in the days. Sure it resulted in a 500Mb executable and crashed the compiler for input arrays larger then a dozen elements but it was constant O(1) time for any input :P
Sorry for offtopic. Nostalgia took me over ;)

Joel Bodenmann

@Chris-Kawa said in Template: Force const parameter:

I'll just assume you really meant pointers to const, because const pointer would be LibraryItem* const, which is entirely different beast.

Your assumption is correct. Sorry for using the wrong terminology. I'll blame not-getting-enough-sleep for it :p

@Chris-Kawa said in Template: Force const parameter:

Here's a stripped down implementation:

Oh boy... This is going to take a while (and lots of reading) for me to understand it. But I appreciate your efforts. Also, experience tells me that all code examples you write/post on this forum always just work, so huge Thank you! although I don't understand it yet :p

@Chris-Kawa said in Template: Force const parameter:

I remember when I wrote template based compile time quick sort back in the days. Sure it resulted in a 500Mb executable and crashed the compiler for input arrays larger then a dozen elements but it was constant O(1) time for any input :P

Is there any blog post / white paper you can link to? Sounds interesting :)

Chris Kawa

I guess the line that need the most explaining is this one:

return Foo<T, std::is_pointer<T>::value && std::is_const<std::remove_pointer<T>::type>::value>::convert(_libraryItems);

All the std magic is just a verbose way of saying "is T a pointer and does it point to a const value" so it's pretty much
Foo<T, true>::convert(_libraryItems) for types that qualify and
Foo<T, false>::convert(_libraryItems) for those that don't.

Foo<T, false> will call into thet deleted specialization and Foo<T, true> into the real conversion.

std::is_pointer<T>::value - this is true for pointers, false for others
std::remove_pointer<T>::type - for any given pointer type it's a typedef for the pointed to type e.g for T being int* it's int.
std::is_const<X>::value - this is true for const types and false for others

Is there any blog post / white paper you can link to? Sounds interesting :)

It was a class assignment over a decade ago. I'm sure the topic has a vast coverage, but I can't give you any links because it's simply useless in practice and I hadn't any interest in it after completing it.

VRonin

I'm definitely in the wrong section of the forum given my knowledge of the language but why wouldn't a simple static_assert work here?

template<class T>
    QList<T> libraryItems() const
    {
static_assert(std::is_pointer<T>::value && std::is_const<std::remove_pointer<T>::type>::value,"You can only use const pointers as template parameters");
        QList<T> list;
\\ etc

Chris Kawa

@VRonin said in Template: Force const parameter:

why wouldn't a simple static_assert work here?

It definitely would.